20#15 Given the following half-reactions and associated standard reduction potentials: AuBr−4(aq)+3e−→Au(s)+4Br−(aq) E∘red=−0.858V Eu3+(aq)+e−→Eu2+(aq) E∘red=−0.43V IO−(aq)+H2O(l)+2e−→I−(aq)+2OH−(aq) E∘red=+0.49V Sn2+(aq)+2e−→Sn(s) E∘red=−0.14V a) Write the cell reaction for the combination...

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Chemistry

20#15

Given the following half-reactions and associated standardreduction potentials:
AuBr−4(aq)+3e−→Au(s)+4Br−(aq)
E∘red=−0.858V
Eu3+(aq)+e−→Eu2+(aq)
E∘red=−0.43V
IO−(aq)+H2O(l)+2e−→I−(aq)+2OH−(aq)
E∘red=+0.49V
Sn2+(aq)+2e−→Sn(s)
E∘red=−0.14V

a) Write the cell reaction for the combination of thesehalf-cell reactions that leads to the largest positive cellemf.

b) Calculate the value of this emf.

E∘max = _____ V

c) Write the cell reaction forthe combination of half-cell reactions that leads to the smallestpositive cell emf.

d) Calculate the value ofthis emf.

E∘min = _____ V

Answer & Explanation Solved by verified expert
3.7 Ratings (580 Votes)
a the highest positive emf will be for the combination where anode has lowest standard reduction potential Cathode has highest standard reduction    See Answer
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