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  3. 2 ex 4r 2r 2 r v part 3 of 3 from the previous ste

2 ex 4r 2r 2 r V Part 3 of 3 From the previous step...

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Calculus

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2 ex 4r 2r 2 r V Part 3 of 3 From the previous step we have ex 42 2r 2 0 Since ex is never 0 then we know 4 2r2 0 Solving the above equation gives the solutions to the quadratic equation smaller value larger value L 11 47 2r 2

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