2. At 500 °C, cyclopropane (C3H6) rearranges to propene (CH3CH=CH2):   C3H6 (g) ------> CH3CH=CH2 (g) The reaction is...
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2. At 500 °C, cyclopropane (C3H6) rearranges to propene(CH3CH=CH2):   C3H6 (g) ------> CH3CH=CH2(g)
The reaction is first order and the rate constant is 6.7 x 10-4s-1. (a) What is the rate law for the reaction, and; (b) if theinitial concentration of C3H6 is 0.100 M, what is the concentrationof cyclopropane of after 20 min?
3. Butadiene (C4H6) reacts with itself at 250 °C to form a dimerwith the formula C8H12.
2 C4H6 (g) ----> C8H12(l)
The reaction is second order in C4H6. (a) What is the rate lawfor the reaction, and; (b) if the rate constant is 4.0 x 10-2M-1.s-1, and the initial concentration ofC4H6 is 0.200 M, how longwill it take for the concentration of C4H6 to reach 0.04 M?
4. Â Â a) In Q. 2 above what is the half life for thereaction and what is concentration of C3H6after 3 half-lives
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  b) In Q. 3 above how long are the first and secondhalf-lives?
2. At 500 °C, cyclopropane (C3H6) rearranges to propene(CH3CH=CH2):   C3H6 (g) ------> CH3CH=CH2(g)
The reaction is first order and the rate constant is 6.7 x 10-4s-1. (a) What is the rate law for the reaction, and; (b) if theinitial concentration of C3H6 is 0.100 M, what is the concentrationof cyclopropane of after 20 min?
3. Butadiene (C4H6) reacts with itself at 250 °C to form a dimerwith the formula C8H12.
2 C4H6 (g) ----> C8H12(l)
The reaction is second order in C4H6. (a) What is the rate lawfor the reaction, and; (b) if the rate constant is 4.0 x 10-2M-1.s-1, and the initial concentration ofC4H6 is 0.200 M, how longwill it take for the concentration of C4H6 to reach 0.04 M?
4. Â Â a) In Q. 2 above what is the half life for thereaction and what is concentration of C3H6after 3 half-lives
 Â
  b) In Q. 3 above how long are the first and secondhalf-lives?
Answer & Explanation Solved by verified expert
C3H6 (g) ------> CH3CH=CH2 (g)
rate law
rate = K[C3H6]1
t    = 20min = 20*60 = 1200sec
K = 2.303/t log[A0]/[A]
6.7*10-4 = 2.303/1200 log0.1/[A]
log0.1/[A]Â Â = 6.7*10-4 *1200/2.303
                  = 3491.1*10-4
log0.1/[A]Â Â Â = 0.34911
   0.1/[A]   = 100.34911
   0.1/[A]   = 2.2341
        [A]   = 0.1/2.2341 = 0.04476M
3. 2 C4H6 (g) ----> C8H12 (l)
     rate = k[C4H6]2 Â
K = 1/t [1/[A0] -1/[A]
t  = 1/K [1/[A] -1/[A0] ]
   = 1/4*10-2 [1/0.04 -1/0.2]
    =25*(25-5)
    = 500sec
4. no of half live = total time/half life time
             3            = 1200/half live time
            half life time = 1200/3 = 400sec
b. 1 = total time /400
  time = 400sec
   2  = total time/400
  time  = 800sec
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