1)Write the complete equation (balanced with states) for the reaction between potassium chloride and lead (II)...

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Chemistry

1)Write the complete equation (balanced with states) for thereaction between potassium chloride and lead (II) nitrate?
2) Which precipitate forms in the above mentioned reaction?
3) You mix 16.00 mL of 0.778 M lead (II) nitrate with 18.00 mLof 0.813 M potassium chloride, and collect and dry the precipitate.Calculate the following:
a) Moles of lead (II) nitrate used:
b)Moles of potassium chloride used:
c) Moles of precipitate expected from lead (II) nitrate:
d) Moles of precipitate expected from potassium chloride:
e) Compare parts c and d to indicate the limiting reactant.
f) What mass of precipitate do you expect to obtain from thisreaction?
g) If the actual yield of the precipitate you recover is 0.916g,what is the percent yield of the precipitate?
show work please

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3.6 Ratings (612 Votes)

1 The reaction between potassium chloride andleadIInitrate isPbNO32aq 2KClaq PbCl2s 2KNO3aq2 LeadIIchloride is the precipitate forms inthe abovementioned reaction3 GivenPbNO32 0778 MVolume of PbNO32 1600 mL x 1L 1000mL 0016 LKCl 0813 MVolume of KCl solution 1800 mL x 1 L 1000 mL 0018 La Moles of leadII See Answer

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