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1)Mercury (II) hydroxide is quite insoluble in water (Ksp of Hg(OH)2 = 3.0×10-26 at 25°C.In which one...

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Chemistry

1)Mercury (II) hydroxide is quiteinsoluble in water (Ksp of Hg(OH)2 =3.0×10-26 at 25°C.In which one of the followingsolutions would you expect Hg(OH)2 to be even lesssoluble than it is in pure water? Why?

(a) 0.1 MNaCl                  (b) 0.1 M HCl                   (c) 0.1 M NaOH               (d) 0.1 M NaCN

2)How will the solubility of calciumfluoride differ in acidic water compared to neutral water? Why?

(a) It will be more soluble in acidicwater

(b) It will be less soluble in acidicwater

(c) The solubility in acidic water andneutral water will be the same

Calculate the Ksp forMg3(PO4)2, given that its molarsolubility is 3.57·10-6 mol/L.

Answer & Explanation Solved by verified expert
3.6 Ratings (478 Votes)

1 ) answer : (c) 0.1 M NaOH

explanation:

Hg (OH)2 <-----------------> Hg+2 + 2OH-

NaOH ---------------------> Na+    + OH-

due to common ion the equilibrium shifts to the left so solubility of Hg(OH)2 decreases

2) answer : (a) It will be more soluble in acidic water

CaF2 <----------------> Ca+2   + 2F-

HCl <---------------->   H + Cl

H + F- --------------> HF

so F- ions are removed by acid H+ . so that will be decrease in concentraion of F- in acid .

3)

Mg3(PO4)2 ----------------> 3 Mg+2   + 2 PO4-3

                                         3S               2S

Ksp = (3S)^3 (4S)^2 = 108 S^5

3.57 x 10^-6 = 108 S^5

S = 0.032 M

solubility   = 0.032 M
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