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1.How many mL of 0.500 M HCl should be added to 155 mL of 0.0500 M...

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Chemistry

1.How many mL of 0.500 M HCl should be added to 155 mL of 0.0500M benzylamine to form a buffer with pH = 8.52? C7H7NH2 pKb = 4.35C7H7NH2 (aq) + H+ (aq) ï‚® C7H7NH3 + (aq) This structure ofbenzylamine has a carbon at the junction of each line with 1hydrogen on each 3-bonded ring C and 2 hydrogens on the C in theside chain attached to the ring carbon. Note that the N atom has 3bonds and a lone pair.

2.Write the formula for the conjugate acid of benzylamine.

Answer & Explanation Solved by verified expert
4.2 Ratings (696 Votes)

benzylamine millimoles = 155 x 0.05 = 7.75

millimoles of HCl = 0.5 x V = 0.5 V

C7H7NH2 (aq) + H+ (aq) -----------------> C7H7NH3 + (aq)

     7.75                0.5 V                                 0           

    7.75 - 0.5V         0                                     0.5V

pH = 14 – { pKb + log[salt/ base ]}

8.52 = 14 - {4.35 + log [0.5V / 7.75 - 0.5V]

[0.5V / 7.75 - 0.5V] = 13.49

V = 14.43 mL

volume of HCl added = 14.43 mL
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