1.Consider hashing with a table size of 100 and a hash function of key%tablesize. Insert 25...

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1.Consider hashing with a table size of 100 and a hash functionof key%tablesize. Insert 25 keys. Do you expect to see anycollisions? Why or why not?

Yes, because random values likely will land on samelocations.
No becase there are four times as many slots as needed.

2. Secondary clustering means that elements that hash to thesame position will probe to the same alternate cells.
Simple hashing uses key%tablesize as the hash function.

Which of the following sequence of insertions would demonstratesecondary clustering of quadratic probing if the tablesize is100?

1,3,5,7,9
Secondary clustering is unlikely with quadratic probing.
1,2,3,4,5,6
259,359,459,559
0,1,4,9,16,25,36,49

3.Using double hashing (as the Collision Resolution technique),consider inserting multiple copies of the same value Is thereclustering?

The table is large enough there is little chance forcollision.
Because neighbors are not used for overflow, clustering doesnot occur.
Each key has a unique step function.
There is clustering. It is impossible to prevent.

4. Consider the following collision resolution scheme: You uselinear probing, but always increment by 3 (rather than 1) in theevent of a collision.

Which is true of this method?

secondary clustering
non-clustering
primary clustering

Answer & Explanation Solved by verified expert
3.6 Ratings (341 Votes)
1yesbecause random values likely will land on dame locations for example suppose two among the 25 keys are 1 and 101 Then 1 100 1101100 1 Both will land on same slot socollision    See Answer
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