19.36: Part A Ca-40 (atomic mass = 39.96259 amu) Express your answer using five decimal places. Mass defect = Â Â amuÂ Â SubmitMy...

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Chemistry

19.36:
Part A
Ca-40 (atomic mass = 39.96259 amu)
Express your answer using five decimal places.
Mass defect = Â Â amuÂ Â
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Part B
Express your answer using four significant figures.
Binding energy per nucleon = MeV/nucleon
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Part C
V-51 (atomic mass = 50.94396 amu)
Express your answer using five decimal places.
Mass defect = Â Â amuÂ Â
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Part D
Express your answer using four significant figures.
Binding energy per nucleon = MeV/nucleon
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Part E
Ag-107 (atomic mass = 106.905092 amu)
Express your answer using five decimal places.
Mass defect = Â Â amuÂ Â
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Part F
Express your answer using four significant figures.
Binding energy per nucleon = MeV/nucleon

Answer & Explanation Solved by verified expert

4.0 Ratings (433 Votes)

Part AMass defect Combined mass of protons and neutrons in the atom actual mass of the atomNo of protons in Ca40 20Mass of 1 proton 100728 amuMass of protons in Ca40 20 100728 amu 201456 amuNo of neutrons in Ca40 20Mass of 1 neutron 100867 amuMass of neutrons in Ca40 20 100867 amu 201734 amuCombined mass of protons and neutrons in Ca40 201456 amu 201734 amu 40319 amuActual atomic mass of Ca40 3996259 amuThereforeMass See Answer

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