19. a. For the titration of 50.00 mL of 0.0500 M Fe2+ with 0.1000 M Ce4+...

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Chemistry

19. a. For the titration of 50.00 mL of 0.0500 M Fe2+ with0.1000 M Ce4+ in the presence of 1 M H2SO4, please calculate thesystem potential after 2.25 mL of Ce4+ is added .
Ce4+ + e ÃÃŽ Ce3+, E0 = + 1.44 V (in 1M H2SO4)
Fe3+ + e ÃÃŽ Fe2+, E0 = + 0.68 V (in 1M H2SO4).
They got Esystem = 0.62 V.
b)Â Â For the same titration as in question (a), whatâ€™sthe system potential after 32.00 mL of Ce4+ is added?
Answer: Esystem = 1.41 V
c) If we set up an electrochemical cell where the cathode is thesystem that we have in question (b), whereas the anode is asaturated calomel electrode (0.2444 V relative to standard hydrogenelectrode). Please determine the potential of this electrochemicalcell.
Answer: Ecell = 1.16 V
d) Please determine the system potential at the equivalencepoint for the titration described in question (a).
Answer: Esystem = 1.06 V
I listed all the answers. I just want to see how they got that.Thanks.

Answer & Explanation Solved by verified expert

3.8 Ratings (442 Votes)

19 a moles of Fe2 005 M x 50 ml 25 mmol mols of Ce4 01 M x 225 ml 0225 mmol Fe2 remaining 2275 mmol5225 ml 0043 M Fe3 formed 0225 mmol5225 ml 00043 M Using See Answer

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