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125.0-mL aliquot of 0.124 M diprotic acid H2A (pK1 = 4.03, pK2 = 8.06) was titrated...

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Chemistry

125.0-mL aliquot of 0.124 M diprotic acid H2A (pK1 = 4.03, pK2 =8.06) was titrated with 1.24 M NaOH. Find the pH at the followingvolumes of base added: Vb = 0.00, 1.80, 6.25, 11.50, 12.50, 13.50,18.75, 24.00, 25.00, and 28.00 mL. (Assume Kw = 1.01 ✕ 10−14.)

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4.5 Ratings (683 Votes)
1 000 mL base added C 0124 M pH 12 pK1 log C pH 12 402 log 0124 pH 246 2 180 mL added millimoles of acid 125 x    See Answer
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