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  3. 1.20cm tall object is 50.0cm to the left of a dive

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal...

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Physics

1.20cm tall object is 50.0cm to the left of a diverging lens(lens 1) of focal length of magnitude 40.0cm. A second converginglens (lens 2) of focal length 60.0cm, is located 300cm to the rightof the first lens along the same optic axis.

(a)Calculate the location of the image (call it I1) formed bythe lens1.

(b) Is image I1 real or virtual?

(c) Is image I1 on left side or right side of lens 1?

(d) Calculate magnification m1 of lens 1. Is image I1 upright orinverted?

(e) Calculate height of the image I1.

(f) I1 is now the object for the second lens. Is the object forlens 2 real or virtual?

(g) Calculate the object distance for lens 2?

(h) Calculate the location of the image I2 produced bylens2.

(i) Calculate magnification m2 of lens2. Is image I2 upright orinverted?

(j) Calculate height of the image I2.

(k) Find overall magnification of these two lens system.

(l) Is final image real or virtual?

(m) Is final image upright or inverted, relative to initialobject?

(n) Is final image enlarged or reduced in size, relative toinitial object?

(o) Draw a diagram showing location of lenses, objects andimages

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