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  3. 10.5 ml of 0.100m ammonium chloride aqueous soluti

10.5 mL of 0.100M ammonium chloride aqueous solution is titrated with 0.100 M NaOH(aq). What type of...

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Chemistry

10.5 mL of 0.100M ammonium chloride aqueous solution is titratedwith 0.100 M NaOH(aq).

What type of solution is present when VNaOH = 2.00mL?

Select one:

a. strong acid

b. strong base

c. weak acid

d. weak base

e. buffered

Answer & Explanation Solved by verified expert
4.3 Ratings (630 Votes)

The number of mols of NH4Cl = (10.5 mL)(0.100 M) = 1.05 mmol

The number of mols of NaOH = (2.00 mL)(0.100 M) = 0.2 mmol

Here, the resultant reaction -

           NH4+ (aq) + OH- (aq) <--------> NH3 (aq) + H2O (l)

         1.05 mmol    0.2 mmol                  0

           -0.2 mmol     -0.2 mmol             +0.2 mmol

          0.85 mmol      0                           0.2 mmol

So the resulting solution will be buffer. So option e) correct.
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