1) You are screening a population of 350 island sheep for coatcolor, and you count 100 black sheep and 250 white sheep. What isp, the frequency of the “black” allele of the TYRP1 gene? Crossingtrue breeding black sheep with true breeding white sheep alwaysresults in 100% black sheep.

a.		p = 0.2857
b.		p = 0.7143
c.		p = 0.8452
d.		p = 0.1548

2) In the same population, if it is under Hardy-Weinbergequilibrium, how many individuals do you expect to be heterozygousat TYRP1?

a.		92
b.		100
c.		8
d.		75

3) You come back after the population has gone through onegeneration, and count 445 white sheep and 208 black sheep. What isthe expected number of heterozygotes in the newgeneration, if this population is in Hardy-Weinbergequilibrium?

a.		171
b.		187
c.		11
d.		208

4) What is the observed number of heterozygotesin the new generation?

a.		535
b.		118
c.		188
d.		156

5) Using the same logic, you get the expected and observednumber of homozygotes in the new generation, and run aχ² test. You find your p-value is 0.8377. Whatcan you say about this population?

a.		This population is in Hardy-Weinberg equilibrium at the TYRP1locus: the TYRP1 is not experiencing any force of evolution.
b.		This population is in Hardy-Weinberg equilibrium at the TYRP1locus: therefore this population is not undergoing any evolution atall.
c.		This population deviates from HWE at the TYRP1 locus: the TYRP1locus is causing nonrandom mating
d.		None of the above