1) The reversible chemical reaction A( a q ) B( a q )C( a q ) D( a q )...

a A B C D 2 2 0 0 2x 2x x x Kc x2 2x2 52 x2x2 x2x sqrt 52 x2x 228 x 456 228x ....

1) The reversible chemical reaction A(aq)+B(aq)â‡ŒC(aq)+D(aq) has the following equilibrium constant: K=[C][D][A][B]=5.2 a) Initially, only A and B are...

Free

50.1K

Verified Solution

Question

Chemistry

1) The reversible chemical reaction
A(aq)+B(aq)â‡ŒC(aq)+D(aq)
has the following equilibrium constant:
K=[C][D][A][B]=5.2
a) Initially, only A and B are present, each at 2.00 mol Lâˆ’1.What is the final concentration of A once equilibrium isreached?
b) What is the final concentration of D at equilibrium if theinitial concentrations are [A] = 1.00 mol Lâˆ’1 and [B] = 2.00 molLâˆ’1 ?

Answer & Explanation Solved by verified expert

4.1 Ratings (659 Votes)

AÂ Â + BÂ Â Â ÃŸÃ CÂ Â +Â Â D

2Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â 0

2-xÂ Â Â Â 2-xÂ Â Â Â Â Â Â Â xÂ Â Â Â Â Â x

Kc = x^2 / (2-x)^2

5.2 = (x/(2-x))^2

x/(2-x) = sqrt (5.2)

x/(2-x) = 2.28

x = 4.56 â€“ 2.28*x

3.28*x = 4.56

x = 1.39 M

[A] = 2-x = 2 â€“ 1.39 = 0.61 M

Answer: 0.61 M

AÂ Â + BÂ Â Â ÃŸÃ CÂ Â +Â Â D

1Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â 0

1-xÂ Â Â Â 2-xÂ Â Â Â Â Â Â Â xÂ Â Â Â Â Â x

Kc = x^2 / (2-x)(1-x)

5.2 = x^2 / (2-3x+x^2)

5.2*x^2 -15.6*x +10.4 = x^2

4.2*x^2 â€“ 15.6*x + 10.4 = 0

solving above quadratic equation we get,

x = 2.84 and x=0.87

x canâ€™t be 2.84 as it will make concentration of A and B negative

so,

x = 0.87 M

[D] = 0.87 M

Answer: 0.87 M

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member