1) The pressure inside a hydrogen-filled container was 2.10 atm at 21 ∘C. What would the...

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Chemistry

1) The pressure inside a hydrogen-filled container was 2.10 atmat 21 ∘C. What would the pressure be if the container was heated to87 ∘C ?

2) At standard temperature and pressure (0 ∘C and 1.00 atm ),1.00 mol of an ideal gas occupies a volume of 22.4 L. What volumewould the same amount of gas occupy at the same pressure and 70 ∘C?

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3.9 Ratings (516 Votes)

Intilal                                               Final

P1 = 2.1atm                                    P2 =

T1   = 21C0 = 21+ 273 =294K                   T2   = 87C0   = 87 + 273 = 360K

              P1/T1    =     P2/T2

              P2    = P1T2/T1

                       = 2.1*360/294 = 2.54atm

2. Intial                                                             Final

V1 = 22.4ml                                                  V2 =

T1   = 0C0 = 273 K                                        T2 = 70C0 = 70 + 273 = 343K

                       V1/T1   = V2/T2

                       V2       = V1T2/T1

                                  = 22.4*343/273   = 28.143L


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