1. Put the general step in order necessary to create bacteriacapable of producing human insulin.

step 1

step 2

step 3

step 4

step 5

a. splice the human insulin DNA into the bacterial plasmid

b. Cut the bacteria plasmid with HindIII

c. Treat bacterial to induce transformation

d. culture bacteria and isolate the protein

e. cut the bacteria plasmid with BamH1

f. isolate and cut the human insulin gene with BamH1

2. Human DNA cut with BamH1 can be joined to

a. human DNA cut with HindiIII

b. bacteria DNA cut with BamH1

c. Human DNA that is uncut

d. none of the above

e. bacterial DNA that is uncut

3. which of the following could not be a recognition site of apalindromic restriction endonuclease?

a. GAATTC

CTTAAG

b. ATCGAT

TAGCTA

c. CTGCAG
GACGTC

d. GCTTGC

CGAACG

e. GGATCC

CCTAGG

4. Because eukaryotic genes contain introns, they cannot betranslated by bacteria, which lack RNA-splicing machinery. But ifyou want to engineer a bacterium to produce a eukaryotic protein(such as insulin), you can synthesize a gene without introns. Thebest way to do this is to:

a. alter the bacteria so that they can splice RNA

b. Use a restriction enzyme to remove introns from the gene

c. work backward from mRNA to make a version of the gene withoutintrons

5. The gene for human growth hormone (HGH) can be inserted intothe genome of bacteria. The bacteria that take up the HGH gene cantranscribe and translate this gene into small quantities of thisprotein. How is this technology possible?

a. bacteria employ the same genetic code as humans

b. Humans require HGH grow normally.

c. Reproductive cloning is possible only in bacteria

d. The genomes of bacteria and human are similar

6. In the process of gel electrophoresis, DNA segment can beseparated from each other based on?

a. the ratio of thymine to adenine base-pairs compared tocytosine to guanine base-pairs

b. the fact that some segments are negatively charged whileothers are positively charged.

c. the fact that some of the DNA will be single-stranded whileothers will be double-stranded

d. the length of each base-pair segment

7. which of the following is not true about restrictionendonucleases?

a. restriction endonucleases cut in an internal region of theDNA

b. Restriction endonucleases are used by bacteria to cut viralDNA

c. restriction endonuclease can produce \"sticky ends.\"

d. Restriction endonucleases are only useful to scientists ifthey cut specific recognition sites.

8. you are given a linear piece of DNA Gel electrophoresis andrestriction digestion results in the following data:

DNA + Ecoli produces two bands of 800bp and 200 bp

DNA + BamHI produces one band of 500 bp

DNA + Ecoli + BamHI produces three bands of 500bp, 300bp, and200bp

Which of the following is not true?

a. there is a single Ecoli recognition site in the DNA

b. There are two Ecoli recognition sites in the DAN

c. There is a single BamHI recognition site in the DAN

d. the uncut DNA would produce a single band of 1.000bp

9. sequences in DNA that restriction enzymes bind to and cut aremostly:

a. random sequences

b. symmetrical about the midpoint

c. antiparallel

d. not symmetrical about the midpoint.

10. the single strand ends of DNA molecules can be joinedtogether by:

a. restriction endonucleases

b. DNA polymerase

c. RNA polymerase

d. DNA ligase

11. If a circular piece of DNA has three sites for a particularrestriction enzyme, how many fragments will be generated bycomplete digestion with that enzyme .................