1). Nitromethane (CH3NO2) burns in air to produce significant amounts of heat. 2CH3NO2(l)+3/2O2(g)→2CO2(g)+3H2O(g)+N2(g) ΔH∘rxn=−1418kJ How much heat...
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Chemistry
1). Nitromethane (CH3NO2) burnsin air to produce significant amounts of heat. 2CH3NO2(l)+3/2O2(g)→2CO2(g)+3H2O(g)+N2(g)ΔH∘rxn=−1418kJ How much heat isproduced by the complete reaction of 6.91 kg ofnitromethane?
2). The air within a cylinder equipped with a piston absorbs 529J of heat and expands from an initial volume of 0.10 L to a finalvolume of 0.87 Against an external pressure of 1.0 atm.What is the change ininternal energy of the air within the cylinder?
3). The propane fuel(C3H8) used in gas barbeques burns according to this thermochemicalequation.C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ​If a pork roast must absorb 1.7×103 kJ to fully cook, andif only 13 % of the heat produced by the barbeque is actuallyabsorbed by the roast, what mass of CO2 is emitted into theatmosphere during the grilling of the pork roast?
4). How much heat is required to warm 1.40 L of waterfrom 20.0 ∘C to 100.0∘C? (Assume a density of 1.0g/mL for thewater.)
1). Nitromethane (CH3NO2) burnsin air to produce significant amounts of heat. 2CH3NO2(l)+3/2O2(g)→2CO2(g)+3H2O(g)+N2(g)ΔH∘rxn=−1418kJ How much heat isproduced by the complete reaction of 6.91 kg ofnitromethane?
2). The air within a cylinder equipped with a piston absorbs 529J of heat and expands from an initial volume of 0.10 L to a finalvolume of 0.87 Against an external pressure of 1.0 atm.What is the change ininternal energy of the air within the cylinder?
3). The propane fuel(C3H8) used in gas barbeques burns according to this thermochemicalequation.C3H8(g)+5O2(g)→3CO2(g)+4H2O(g)ΔH∘rxn=−2044kJ​If a pork roast must absorb 1.7×103 kJ to fully cook, andif only 13 % of the heat produced by the barbeque is actuallyabsorbed by the roast, what mass of CO2 is emitted into theatmosphere during the grilling of the pork roast?
4). How much heat is required to warm 1.40 L of waterfrom 20.0 ∘C to 100.0∘C? (Assume a density of 1.0g/mL for thewater.)
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