1 - For the insoluble salt lead (ii) phosphate Pb3(PO4)2, the solubility product, Ksp is 3.10x10-44 a- Write...

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Chemistry

1 - For the insoluble salt lead (ii) phosphatePb₃(PO₄)₂, the solubility product,Ksp is 3.10x10^-44
a- Write the chemical equation andsolubility product expression forPb₃(PO₄)₂
b- Determine the molar solubility (M) ofPb₃(PO₄)₂
c- Identify wheather the molar solubility ofPb₃(PO₄)₂ will increase ordecrease upon the following changes and explainwhy?
* The ddition of 0.10 MPb(NO₃)₂
* The addition of 0.10 M NaCl

Answer & Explanation Solved by verified expert

3.6 Ratings (538 Votes)

Given that Ksp of Pb₃(PO₄)₂ = 3.10 x 10^-44

Pb₃(PO₄)₂ ---------------> 3 Pb²⁺ + 2 PO₄^3-

_{Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â}Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3sÂ Â Â Â Â Â Â Â Â Â Â 2sÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â s = molar solubility of Pb₃(PO₄)₂

Ksp = [Pb²⁺]³ [PO₄^3-]²

Â Â 3.10 x 10^-44 = (3s)³ (2s)²

3.10 x 10^-44 = 108 s⁵

s = [3.10 x 10^-44 / 108]^1/5

= 0.78 x 10^-9 M

Therefore, molar solubility of Pb₃(PO₄)₂ = 0.78 x 10^-9 M

c) Molar solubility (M) of Pb₃(PO₄)₂ after the addition of 0.10 M Pb(NO₃)₂

_{Â Â Â Â Â Â Â Â Â} Dut to common ion Pb2+ in Pb(NO₃)₂ and Pb₃(PO₄)_{2 ,} molar solubility of Pb₃(PO₄)₂ decreases.

Molar solubility (M) of Pb₃(PO₄)₂ after the addition of 0.10 M NaCl

Since there is no common ion, molar solubility of Pb₃(PO₄)₂ is not effected.

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