1 Determine G o for the following reaction 2 Na(s) 2 H 2 O(l) ...

1 2Nas 2Na aq 2e E0 271v 2H2Ol 2e H2g 2OH aq E0 083v 2 Nas 2 H 2 Ol H 2 g 2 OH aq 2 N ....

1. Determine Î”Go for the following reaction: 2 Na(s) + 2 H2O(l) --> H2(g) + 2 OH-(aq)...

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Chemistry

1. Determine Î”G^o for the following reaction:
2 Na(s) + 2 H₂O(l) --> H₂(g) + 2OH^-(aq) + 2 Na⁺(aq)
2. Calculate K for the oxidation of iron by H⁺:
2 Fe(s) + 6 H⁺(aq) --> 2 Fe³⁺(aq) + 3H₂(g)

Answer & Explanation Solved by verified expert

3.6 Ratings (513 Votes)

Â Â 2Na(s) ------------------> 2Na^+ (aq) + 2e^-Â Â Â Â Â E0Â Â = 2.71v

2H2O(l) +2e^- -------> H2(g) + 2OH^- (aq)Â Â Â Â Â Â Â E0 = -0.83v

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2 Na(s) + 2 H₂O(l) --> H₂(g) + 2 OH^-(aq) + 2 Na⁺(aq)Â Â Â E0cell = 1.88v

n = 2

Î”G^oÂ Â Â = -nE0cell*F

Â Â Â Â Â Â Â Â Â Â = -2*1.88*96500

Â Â Â Â Â Â Â Â Â Â = -362840J/mole Â Â = -362.84KJ/mole

2Fe(s) --------------> 2Fe^3+(aq) + 6e^-Â Â Â Â Â Â E0 = 0.04v

6H^+ (aq) + 6e^- ------> 3H2(g)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â E0Â Â = 0.00v

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2 Fe(s) + 6 H⁺(aq) --> 2 Fe³⁺(aq) + 3 H₂(g)Â Â Â Â E0cell = 0.04v

n = 6

Î”G^oÂ Â Â = -nE0cell*F

Â Â Â Â Â Â Â Â Â Â = -6*0.04*96500

Â Â Â Â Â Â Â Â Â Â Â Â Â = -23160J/mole

Î”GoÂ Â Â = -RTlnK

-23160Â Â = -8.314*298*2.303logK

-23160 = -5705.84logK

logKÂ Â Â Â Â Â Â Â = -23160/-5705.84

logKÂ Â Â Â Â Â Â Â = 4.06

KÂ Â Â Â Â Â Â Â Â Â Â Â = 10^4.06Â Â = 1.15*10^4 >>>>answer

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