1) Calculate how many moles of NH3 form when each quantity of reactant completely reacts according...

90.2K

Verified Solution

Question

Chemistry

1) Calculate how many moles of NH3 form when each quantity ofreactant completely reacts according to the equation: 3N2H4(l)â†’4NH3(g)+N2(g)
A) 35.3 g N2H4 -Express your answer using threesignificant figures.
B) 14.9 kg N2H4 - Express your answer using three significantfigures.
2) For each reaction,calculate the mass of the product that forms when 12.5 g of thereactant in red completely reacts. Assume that there is more thanenough of the other reactant.
a) 2K(s)+Cl2(g)â†’2KCl(s) b)2K(s)+Br2(l)â†’2KBr(s) c) 4Cr(s)+3O2(g)â†’2Cr2O3(s) d)2Sr(s)+O2(g)â†’2SrO(s)
3) Nitrogen dioxide reacts with water to form nitric acid andnitrogen monoxide according to the equation:3NO2(g)+H2O(l)â†’2HNO3(l)+NO(g)
Suppose that 3.7 mol NO2 and 1.2 mol H2O combine and reactcompletely. Which reactant is in excess? Express your answer as a chemicalformula.
4) Calculate the molarityof each of the following solutions:
A) 0.19 mol of LiNO3 in 5.48 L ofsolution - Express your answer using two significant figures.B) 62.1 g C2H6O in 2.18 L ofsolution - Express youranswer using three significant figures.
C) 16.14 mg KI in 106 mL of solution -Express your answer using threesignificant figures.
Thank you so much in advance!

Answer & Explanation Solved by verified expert

4.1 Ratings (692 Votes)

3N2H4l 4NH3g N2g Molar mass of N2H4 32 gmole Thus moles of N2H4 in 353 g of it massmolar mass 35332 1103 moles of N2H4 in 14900 g of it massmolar mass 1490032 465625 A 353 g N2H4 Thus moles of See Answer

Get Answers to Unlimited Questions

Join us to gain access to millions of questions and expert answers. Enjoy exclusive benefits tailored just for you!

Membership Benefits:

Unlimited Question Access with detailed Answers
Zin AI - 3 Million Words
10 Dall-E 3 Images
20 Plot Generations
Conversation with Dialogue Memory
No Ads, Ever!
Access to Our Best AI Platform: Flex AI - Your personal assistant for all your inquiries!

Become a Member