1) An observer fails to check the bubble of a level and it isoff two divisions on a 100-m sight. If the sensitivity of thebubble is 20-sec, what error would there be in the reading? 2 ) Thefollowing azimuths are from the north: 329°20’, 180°35’, 48°32’,170°30’, 145°25’, 319°35’, 350°45’, 95°49’, 11°30’, 235°45’.Express these directions as (a) azimuth from the south, (b) backazimuths, (c) bearings. 8) 6.7 The following azimuths are reckonedfrom the north: FE = 4°25’, ED = 90°15’, DC = 271°32’, CB =320°21’, and BA = 190°45’. What are the corresponding bearings?What are the deflections angles between consecutive lines? 9) 6.8The interior angles of a five-sided closed polygon ABCDE are asfollows: A, 120°24’; B, 80°15’; C, 132°24’; D, 142°20’. The angle Eis not measured. Compute the angle at E, assuming the given valuesto be correct.’ 10) 6.11 In an old survey made when the declinationwas 4°15’E, the magnetic bearing of a given line was N35°15’E. Thedeclination in same locality is now 1°10’W. What are the truebearing and the present magnetic bearing that would be used inretracing the line? 11) The following bearings taken on a closedcompass and fill up the table. Lines Bearings (deg-min) Azimuth NDeflection Angles Angle to the Right Interior Angles AB S 37-30 E ?83°45’ 163°45’ ? BC S 43-30 W ? ? ? ? CD N 73-30 W ? ? ? ? DE N11-45 E ? ? ? ? EF ? ? ? ? ? 12) ILLUSTRATE THE TRAVERSE AND SHOWTHE SOLUTIONS. Transform graphically into a figure with sidescontaining unknown quantities are made adjoining. Determine theunknown quantities. Course Length Bearing AB 492.98 N 05°30’ E BCUNKNOWN S 12°17’ E CD 845.85 N 46°03’ E DE 852.18 S 67°24’ E EF1210.50 UNKNOWN FA 661.26 N 55°27’ W AB BC CD DE EF FA 13)ILLUSTRATE THE TRAVERSE AND SHOW THE SOLUTIONS. Transformgraphically into a figure with sides containing unknown quantitiesare made adjoining. Determine the unknown quantities. Course LengthBearing AB 249.18 S 19°32’ E BC UNKNOWN N 74°09’ E CD 445.10 S36°40’ E DE 668.27 S 51°14’ W EF 866.79 N 73°25’ W FG UNKNOWN N26°00’ W GA 560.15 N 64°32’ E 14) Given Below is the technicaldescription of lot 2061, Cebu Cadastre. Line Length (m) Azimuthfrom South 1-2 22.04 S 32°17’ W 2-3 10.00 N 36°35’ W 3-4 5.00 N15°47’ W 4-1 19.95 N 73°07’ E 1. Find the area of the lot by DMDmethod. 2. Find the area of the lot by DPD method. 15) Compute forthe following and show the tabulated solutions: (Notes: Use 2decimal places for all corrections and lengths, degrees and minutesfor angles) Line Length (m) Azimuth from South AB 1020.87 168°35’BC 1117.26 263°30’ CD 660.08 304°25’ DE 495.85 5°30’ EF 850.6246°15’ FA 855.45 112°30’ 1. Using Compass Rule, solve for adjustedlatitudes, departures, distances and bearings for all the traverselines 2. Using Transit Rule, solve for adjusted latitudes,departures, distances and bearings for all the traverse lines 3.Using coordinate method and using the result of balancing traversein # 2 (transit rule) with station A (N,E) coordinates = (20000,20000), solve for the coordinates (N, E) of all traverse stationsand the area of the traverse 4. Using DMD method and using theresult of balancing traverse in # 2 (transit rule), solve for areaof the traverse 5. Using DPD method and using the result ofbalancing traverse in # 2 (transit rule), solve for area of thetraverse 16) At regular interval of 5 meters along line AB, themeasured offset distances from the line AB to the edge of thestream are: 6.5, 7.3, 12.1, 12.7, 14.5, 16.0, 18.6, 18.5, 16.4,15.9, 14.7, 13.5, 12.75, 12.5, 9.7 and 2.0. What is the areabetween line AB and the stream?
