1. A student prepares a 250.0 mL solution using 41.7 grams of potassium nitrite. They then...

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Chemistry

1. A student prepares a 250.0 mL solution using 41.7 grams ofpotassium nitrite. They then take 29.9 mL of this solution anddilute it to a final volume of 250.0 mL. How many grams ofpotassium nitrite are in a 36.2 mL sample of this final dilutedsolution?

2.

If you wanted to make a 4.50 M solution of aluminum nitrateusing a 400.00 mL volumetric flask, how many grams of this saltwould you need to use?

3.

H2SO4 +2KOH  →  2H2O +K2SO4

How many mL of a 1.75 M solutionof potassium hydroxide are required to titrate 15.72 mL of a 2.13 Msolution of sulfuric acid?

Answer & Explanation Solved by verified expert
4.3 Ratings (811 Votes)
Answer 1 We are given mass of KNO2 417 g volume 2500 mL First we need to calculate the moles of KNO2 Moles of KNO2 417 g 85104 gmol1 0490 moles So initial concentration of KNO2 0490 moles 0250 L 196 M So M1 196 M V1 299 mL V2 2500 mL M2 By dilution    See Answer
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