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  3. 1. a) calculate the solubility of pb3(po4)2 in wat

1. a) Calculate the solubility of Pb3(PO4)2 in water. b) Calculate the solubility of Hg2Br2 in water...

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Chemistry

1.

a) Calculate the solubility of Pb3(PO4)2 in water.

b) Calculate the solubility of Hg2Br2 in water and in 0.300 MCaBr2. Explain why the solubilities are different in water and in0.300 M CaBr2.

Answer & Explanation Solved by verified expert
3.8 Ratings (635 Votes)

   a. Pb3(PO4)2 ----------> 3Pb+2 + 2PO43-

                                           3s       2s

    Ksp           = [Pb+2]3[PO43-]2

     1*10-54    = (3s)3 *(2s)2

                    = 108s5

s5                = 1*10-54/108

                    = 0.0926*10-55

s                  = 4.5*10-12 M

solubility of Pb3(PO4)2 is 4.5*10-12 M

b.            Hg2Br2 ---------> Hg22+ + 2Br-

                                         0           0.3

                                        s           0.3+2s

          Ksp    = [Hg22+][Br-]2

           6.4*10-23   = s*(0.3+2s)2

              s             = 1.4*10-17

due to commom ion effect solubilities are different in water and inCaBr2.

         
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