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1- A 30.00 mL wine sample is titrated with a 1.10×10-1M solution of sodium hydroxide. The...

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Chemistry

1- A 30.00 mL wine sample is titrated with a1.10×10-1M solution of sodium hydroxide. The equivalencepoint is determined to be 34.705 mL. What is the acidity of thewine expressed as (g tartaric acid / L; MW tartaric acid = 150.085g/mole)?

2- The acidity of a wine sample is 1.15×101,expressed as (g citric acid / L wine; MW citric acid = 192.124g/mole) . The sample is titrated with a 0.100 M solution of sodiumhydroxide. The equivalence point is determined to be 23.391 mL.What is the volume of the wine sample analyzed in mL?

Answer & Explanation Solved by verified expert
4.3 Ratings (823 Votes)
1 volume of wine sample 30 ml no of mole of NaOH M V 1110134705 382 mmole 1 mole wine tartaric acid 2    See Answer
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