0.308 g magnesiumsulphate, that contains crystal water, is dissolved in water, sÃ¥ the total volume is...

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Chemistry

0.308 g magnesiumsulphate, that contains crystal water, isdissolved in water, sÃ¥ the total volume is 125.0 mL. To completelyprecipitate the suflation as barium sulfate in 25.0 mL of thissolution, 5.0 mL of 0.050 M barium hydroxide is required.
Calculate how many moles of crystal water are in 1 mole ofmagnesium sulfate.
I am lost in this one, hope for some help :)

Answer & Explanation Solved by verified expert

3.6 Ratings (385 Votes)

Let the magnesium sulphate contains x molecules ofH2O attached with itTherefore the molecular formula will beMgSO4xH2OTherefore the molecular mass 2432 32 64 18x 12032 18x g mol1The amount of MgSO4xH2O taken is 0308 g 0308 12032 18x molesof See Answer

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