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3.6 Ratings (352 Votes)

CH3NH3Br <====> CH3NH3+ + Br-

CH3NH3+ + H2O <===> CH3NH2 + H3O+

ICE table:

                        CH3NH3+              CH3NH2                   H3O+

initial                  0.12                       0                            0

change    -x +x    +x

equilibrium (0.12 - x) x                            x

pKb = -logkb = 3.35

pKa = 14 - 3.35 = 10.65

Ka = antilog(-pKa) = 2.23 x 10-11

Ka = x2/0.12     (0.12 >> x)

2.23 x 10-11 x 0.12 = x2

x = 1.63 x 10-6 = [H+]

pH = -log[H+]

pH = 5.78


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